We show that for α≥, the following inequality holds:
for every function g on (−1,1)
satisfying ∥g∥2 =
∫−11(1
−x2)|g′(x)|2dx
<∞ and ∫−11e2g(x)xdx = 0. This improves a result of Feldman et
al., 1998, and answers a question of Chang and Yang in the
axially symmetric case.